?

The tendency of an element to form an ion is determined by its ionization energy. Simply put, the ionization energy is the amount of energy required to remove an electron from the element. As such, elements with a low ionization energy, such as sodium (Na) and magnesium (Mg), will have a greater tendency to form ions. On the other hand, elements with relatively high ionization energies, such as calcium (Ca), potassium (K) and selenium (Se), will have a lesser tendency of forming ions.

The paper 1 First ionization energy states that fluorine (F2) has the least tendency to be reduced, meaning that it has the highest ionization energy and is least likely to form an ion.

The trends flashcards 2 An element with low ionization energy also discusses how elements with low ionization energies, such as sodium (Na+) and magnesium (Mg2+), will have a greater tendency to form ions.

The Brainly discussion 3 Which of the following elements has the least tendency to form an ion? states that elements like calcium (Ca), potassium (K) and selenium (Se) have relatively low ionization energies and will therefore have a lesser tendency of forming ions.

In conclusion, fluorine (F2) is the element with the least tendency to form an ion, due to its high ionization energy. Elements such as sodium (Na+), magnesium (Mg2+), calcium (Ca), potassium (K) and selenium (Se) all have relatively low ionization energies and will therefore have a greater probability of forming ions.