# Determine The Number Of Moles Of Sodium In 3.20 Moles Of Sodium Hydrogen Phosphate

Sodium hydrogen phosphate (NaH2PO4) is a compound made up of two elements, sodium and hydrogen. In 3.20 moles of sodium hydrogen phosphate, the number of moles of sodium can be determined using the molecular formula. Each molecule of NaH2PO4 contains two moles of sodium, so in 3.20 moles of sodium hydrogen phosphate there are 6.4 moles of sodium.

In order to find out how many grams of sodium are present in 3.20 moles of sodium hydrogen phosphate, you can use the molar mass of NaH2PO4, which is 119.98 g/mol. This means that for every mole of NaH2PO4, there is 119.98 grams. Since there are 6.4 moles of sodium in 3.20 moles of sodium hydrogen phosphate, the total amount of sodium present is 767.712 grams (6.4 moles x 119.98 g/mol).

To find out the volume of sodium present in 3.20 moles of sodium hydrogen phosphate, you can use the density of NaH2PO4, which is 1.71 g/cm3. This means that for every 1 gram of NaH2PO4, there is 1.71 cm3 of volume. Using this formula and the total mass of sodium present in 3.20 moles of NaH2PO4 (767.712 g), the total volume of sodium hydrogen phosphate is 441.23 cm3 (767.712 g x 1.71 cm3/g).