Compound potassium nitrate (KNO3) is composed of one potassium atom, one nitrogen atom, and three oxygen atoms. To answer the question of how many moles of oxygen are in 45.7 moles of potassium nitrate requires a simple calculation. The answer is found by multiplying the number of moles of potassium nitrate (45.7) by the number of oxygen atoms per mole of potassium nitrate (3), which yields 136.1 moles of oxygen.
To better understand the answer to this question, it is important to look at the individual components of the compound. Potassium is an element with a single atom in each mole of a compound and is represented by the symbol K. Nitrogen (N) is also an element with one atom per mole of a compound. While oxygen (O) is an element with three atoms per mole of a compound. When combined, these three elements form the compound potassium nitrate (KNO3).
To calculate the number of moles of oxygen in 45.7 moles of potassium nitrate, the following equation can be used:
Number of Moles of Oxygen = (Number of Moles of Potassium Nitrate) x (Number of Oxygen Atoms Per Mole of Potassium Nitrate)
Using the equation above, it can be determined that 45.7 moles of potassium nitrate would yield 136.1 moles of oxygen (45.7 x 3 = 136.1).
To learn more about the mass of oxygen contained in 1 kg of potassium nitrate (KNO3), one can refer to the web search results listed above. The first result indicates that the mass of oxygen contained in 1 kg of potassium nitrate is 478.5 g. The second result mentions that potassium nitrate decomposes on heating, producing potassium oxide and gaseous nitrogen and oxygen. Finally, the third result discusses how to find the mass of oxygen contained in 1 kg of potassium nitrate. All of these results provide a better understanding of the answer to the query.